Need Help?

Subscribe to Thermodynamics

Subscribe
  • Notes
  • Comments & Questions

$$
\begin{array}{l}{\text { Determine the specific volume of superheated water vapor at } 15 \mathrm{MPa} \text { and } 350^{\circ} \mathrm{C} \text { , }} \\ {\text { using }(\mathrm{a}) \text { the ideal-gas equation, (b) the generalized compressibility chart, }} \\ {\text { and }(\mathrm{c}) \text { the steam tables. Also determine the error involved in the first two cases. }}\end{array}
$$

$$
A-1 \longrightarrow R=0.4615
$$$$
\frac{ KPa. m^{3}}{kg.k}
$$

$$
T_{c r}=647.1 \mathrm{k}
$$

$$
P_{c r}=22.06 \mathrm{MPa}
$$

(a) $$
P v=R t \longrightarrow V=\frac{R T}{\rho}=\frac{0.4615*623.15}{15000}
$$

$$
=0.01917 \mathrm{m}^ 3 / \mathrm{kg}
$$

(b) $$
T_{R}=\frac{T}{T_{cr}}=\frac{673 K}{647.1 k}
$$$$
=1.04 \longrightarrow \text {fig} A-15
$$

\(∴ Z=0.65 \longrightarrow V= Z_{v \ ideal}=0.65*0.01917 \)

$$
=0.01246 \mathrm{m}^ 3/ \mathrm{kg}
$$

(c) $$
A-6 \rightarrow V=0.01148 m^3/kg
$$

(a) $$
\text { error }=\frac{|0.01917-0.01148|}{0.01148} * 100 \%=67 \%
$$

(b) $$
\text { error }=\frac{|0.01 246-0.01148 |}{0.01148} * 100 \%=8.5 \%
$$

$$
\text { ideal } \longrightarrow \quad P v=R T
$$

$$
\text { Real Gags } \longrightarrow P v=Z R T
$$

No comments yet

Join the conversation

Join Notatee Today!