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A particle has charge \(-3.00 \mathrm{nC}\) . (a) Find the magnitude and direction of the electric field due to this particle at a point
0.250m directly above it. (b) At what distance from this particle does its electric field have a magnitude of 12.0 N/C?

\(q=-3nC\)

\( r=0.25 \mathrm{m} \)

 

\( E=432 \mathrm{N/C} \)

\( r=? \quad (a)  E=12 N / C \)

\( E=K \frac{|q|}{r^{2}} \Rightarrow r=\sqrt{\frac{k|q|}{E}} \)

\( r=\sqrt{\frac{8 \cdot 99 * 10^{9}+3 * 10^{-9}}{12}}=1.5m \)

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