${ message }
Your cart is empty
Discount (${discount_percentage}%) : - ${discount}KD
Need Help?
How good was the graphics ?
How well did you understood the video ?
Was the video helpful?
Was the notes helpful?
Sign up to try our free practice
KD
21.500
1 month
Add to cart
42.500
4 months
Subscribe to Thermodynamics
Practice (Free)
Practice
liquids and solids can be approximated as incompressiblesubstances since their specific volumes remain nearly constant during aprocess
$$d s=\frac{d u}{T}=\frac{c d T}{T}$$
The entropy change during a process:
Liquids, solids: $$\quad s_{2}-s_{1}=\int_{1}^{2} c(T) \frac{d T}{T} \cong c_{\mathrm{avg}} \ln \frac{T_{2}}{T_{1}} \quad(\mathrm{kJ} / \mathrm{kg} \cdot \mathrm{K})$$
Isentropic:$$\quad s_{2}-s_{1}=c_{\mathrm{avg}} \ln \frac{T_{2}}{T_{1}}=0 \quad \longrightarrow \quad T_{2}=T_{1}$$
$$d s=c_{v} \frac{d T}{T}+R \frac{d v}{v}$$
$$s_{2}-s_{1}=\int_{1}^{2} c_{v}(T) \frac{d T}{T}+R \ln \frac{v_{2}}{v_{1}}$$
$$s_{2}-s_{1}=\int_{1}^{2} c_{p}(T) \frac{d T}{T}-R \ln \frac{P_{2}}{P_{1}}$$
No comments yet
liquids and solids can be approximated as incompressiblesubstances since their specific volumes remain nearly constant during aprocess
$$d s=\frac{d u}{T}=\frac{c d T}{T}$$
The entropy change during a process:
Liquids, solids: $$\quad s_{2}-s_{1}=\int_{1}^{2} c(T) \frac{d T}{T} \cong c_{\mathrm{avg}} \ln \frac{T_{2}}{T_{1}} \quad(\mathrm{kJ} / \mathrm{kg} \cdot \mathrm{K})$$
Isentropic:$$\quad s_{2}-s_{1}=c_{\mathrm{avg}} \ln \frac{T_{2}}{T_{1}}=0 \quad \longrightarrow \quad T_{2}=T_{1}$$
$$d s=c_{v} \frac{d T}{T}+R \frac{d v}{v}$$
$$s_{2}-s_{1}=\int_{1}^{2} c_{v}(T) \frac{d T}{T}+R \ln \frac{v_{2}}{v_{1}}$$
$$s_{2}-s_{1}=\int_{1}^{2} c_{p}(T) \frac{d T}{T}-R \ln \frac{P_{2}}{P_{1}}$$
No comments yet
Join the conversation