Need Help?

Subscribe to Differential Equation

Subscribe
  • Notes
  • Comments & Questions

Find a lower bound for the radius of convergence of $$\left(x^{2}-2 x-3\right) y^{\prime \prime}+x y^{\prime}+4 y=0$$ about $$x 0=\{5,-5,0\}$$

$$\left(x^{2}-2 x-3\right) y^{\prime \prime}+x y^{\prime}+4 y=0$$

$$p(x)=x^{2}-2 x-3=0 \rightarrow(x-3)(x+1)=0$$

$$x=3, x=-1$$

$$x{0}=5$$

 

No comments yet

Join the conversation

Join Notatee Today!