${ message }
Your cart is empty
Discount (${discount_percentage}%) : - ${discount}KD
Need Help?
How was the speed of the video ?
How well did you understood the video ?
Was the video helpful?
Was the notes helpful?
Sign up to try our free practice
KD
21.500
1 month
Add to cart
42.500
4 months
Subscribe to Thermodynamics
Practice (Free)
Practice
$$ \text { What is the temperature of the heated air at } 150^{\circ} \mathrm{C} \text { in }^{\circ} \mathrm{F} \text { and } \mathrm{R} ? $$
$$ T(^{\circ}{F})=1.8 T(c^{\circ})+32=1.8(150)+32=302 \ ^{\circ} \mathrm{f} $$
$$ T(R)=T(^{\circ}F)+460=302+460=762 R $$
$$ \begin{array}{l}{\text { The temperature of a system rises by } 45^{\circ} \mathrm{C} \text { during a heating process. }} \\ {\text { Express this rise in temperature in kelvins. }}\end{array} $$
$$ \Delta T(k)=\Delta T(^\circ{c}) $$
$$ 45 k=45^{\circ} \mathrm{C} $$
$$ \Delta { F: 10F } $$
$$ \Delta T=\frac{10}{1.8}=5.6 \ ^\circ{c} $$
$$ \Delta T=\frac{10}{1.8}=5.6 k $$
$$ \Delta T=10 \ ^{\circ} F=10 R $$
No comments yet
$$
\text { What is the temperature of the heated air at } 150^{\circ} \mathrm{C} \text { in }^{\circ} \mathrm{F} \text { and } \mathrm{R} ?
$$
$$
T(^{\circ}{F})=1.8 T(c^{\circ})+32=1.8(150)+32=302 \ ^{\circ} \mathrm{f}
$$
$$
T(R)=T(^{\circ}F)+460=302+460=762 R
$$
$$
\begin{array}{l}{\text { The temperature of a system rises by } 45^{\circ} \mathrm{C} \text { during a heating process. }} \\ {\text { Express this rise in temperature in kelvins. }}\end{array}
$$
$$
\Delta T(k)=\Delta T(^\circ{c})
$$
$$
45 k=45^{\circ} \mathrm{C}
$$
$$
\Delta { F: 10F }
$$
$$
\Delta T=\frac{10}{1.8}=5.6 \ ^\circ{c}
$$
$$
\Delta T=\frac{10}{1.8}=5.6 k
$$
$$
\Delta T=10 \ ^{\circ} F=10 R
$$
No comments yet
Join the conversation