${ message }
Your cart is empty
Discount (${discount_percentage}%) : - ${discount}KD
Need Help?
How was the speed of the video ?
How well did you understood the video ?
Was the video helpful?
Was the notes helpful?
Sign up to try our free practice
KD
6.450
1 month
70% off
21.500
Add to cart
12.750
4 months
42.500
Subscribe to Circuit
Practice (Free)
Practice
$$ \begin{array}{l}{\text { Use the node-voltage method to find } v \text { in the }} \\ {\text { circuit shown. }}\end{array} $$
خطوات الحل
(1) $$ \text { reference node } $$
(2) $$ V_{3}, V_{2}, V_{1} $$ non refernce node
(3) $$ \left[\sum\left(\frac{1}{R}\right)\right] V_1-\left[\sum\frac{1}{R}\right]V_2=\sum I $$
$$ \text { at } V_1 $$
$$ \left[\frac{1}{1}+\frac{1}{8}\right] V_{1}-\frac{1}{8} V_2=4.5 \longrightarrow (1) $$
$$ \text {at} V_2 $$
$$ \left(\frac{1}{8}+\frac{1}{12}+\frac{1}{4}\right)V_2-\frac{1}{8}V_1=75\longrightarrow (2) $$
Solve (1) , (2) $$ V_{1}=6 V $$ , $$ V_{2}=18 \mathrm{V} $$
$$ \text { KVL } $$
$$ c l \cdot 1 $$
$$ -V+I*6+V_1=0 $$
$$ -V+? ?*6+6 $$
$$ I=\frac{V_{2}-V_{1}}{2+6} $$
$$ I=\frac{18-6}{8}=1.5 \mathrm{A} $$
$$ -V+1.5 * 6+6=0\Rightarrow V=15V $$
No comments yet
$$
\begin{array}{l}{\text { Use the node-voltage method to find } v \text { in the }} \\ {\text { circuit shown. }}\end{array}
$$
خطوات الحل
(1) $$
\text { reference node }
$$
(2) $$
V_{3}, V_{2}, V_{1}
$$ non refernce node
(3) $$
\left[\sum\left(\frac{1}{R}\right)\right] V_1-\left[\sum\frac{1}{R}\right]V_2=\sum I
$$
$$
\text { at } V_1
$$
$$
\left[\frac{1}{1}+\frac{1}{8}\right] V_{1}-\frac{1}{8} V_2=4.5 \longrightarrow (1)
$$
$$
\text {at} V_2
$$
$$
\left(\frac{1}{8}+\frac{1}{12}+\frac{1}{4}\right)V_2-\frac{1}{8}V_1=75\longrightarrow (2)
$$
Solve (1) , (2) $$
V_{1}=6 V
$$ , $$
V_{2}=18 \mathrm{V}
$$
$$
\text { KVL }
$$
$$
c l \cdot 1
$$
$$
-V+I*6+V_1=0
$$
$$
-V+? ?*6+6
$$
$$
I=\frac{V_{2}-V_{1}}{2+6}
$$
$$
I=\frac{18-6}{8}=1.5 \mathrm{A}
$$
$$
-V+1.5 * 6+6=0\Rightarrow V=15V
$$
No comments yet
Join the conversation